What will happen when the variable y is calculated in the scope where variable x is local?

When the variable y is calculated in a scope where variable x is local, it will result in an error for an unknown identifier if y attempts to reference x or depends on its value. In this scenario, the value of x exists only within its defined local scope and is not accessible outside of it. This is a fundamental principle in programming known as variable scope, where local variables are not visible beyond the block or function in which they are declared.

If y relies on x, such as trying to use its value to perform a calculation, the interpreter will not recognize x in the broader context, hence leading to an error that indicates that x is not defined or known in that scope. This reinforces the concept of scoping in programming, where a variable's accessibility is limited to the region it's declared in, ensuring that local variables do not interfere with variables that may have the same name in different scopes. Thus, if an identifier is not recognized, it confirms the principles of scope management in coding.