What is the value of x after calling the function that initializes its own local x?

To determine the value of x after calling the function, it's important to understand scope and how local variables work in programming. When a function initializes its own local variable named x, that variable is separate from any variable x that exists outside the function's scope. This means that any changes made to the local x do not affect the global or outer scope x unless specifically stated through return values or other methods of sharing data.

If the function in question initializes local x and assigns it a value of 13, then when the function is executed, the local x becomes 13. Since local variables cease to exist once the function execution is complete, any reference to x after the function call would pertain to the global variable, unless the function explicitly returns or modifies the global variable.

In this case, assuming the function initializes x with a value of 13, then after the function call, local x is 13 but does not affect the outer x unless specified. Thus, if the question is specifically about the value of this initialized local x within the function's context, the correct answer is indeed 13. This means after executing that particular function, where the local x was assigned the value of 13, it reflects the local context of that function’s operation